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| 11:10.11 | salgado | so, if PersonLanguage.person is a foreign key to the Person table, should the following work? |
| 11:10.13 | salgado | origin = [Person, Join(PersonLanguage, Person.id == PersonLanguage.person)] |
| 11:11.13 | salgado | I get a TypeError when I try it: |
| 11:11.15 | salgado | <PROTECTED> |
| 11:11.15 | salgado | <PROTECTED> |
| 11:11.15 | salgado | TypeError: Expected int, found <class 'storm.references.Reference'>: <storm.references.Reference object at 0xb87524c> |
| 11:12.20 | salgado | niemeyer, can you help me out with that? |
| 11:12.54 | niemeyer | salgado: Hey! |
| 11:13.15 | niemeyer | salgado: I think it should be either PersonLanguage.person == Person, or PersonLanguage.person_id == Person.id |
| 11:13.39 | niemeyer | salgado: (or whatever the ID naming convention is) |
| 11:14.15 | salgado | a-ha |
| 11:14.18 | salgado | that should be it |
| 11:17.39 | salgado | niemeyer, thanks a lot, I was expecting it to work just like "LeftJoin(Person, AnswerContact.person == Person.id)", but maybe that one works because I use the actual ID column (Person.id) rather than a foreign key to it? |
| 11:18.17 | niemeyer | salgado: It may work because of the order of arguments |
| 11:18.42 | niemeyer | salgado: Person.id doesn't know how to compare itself to a reference |
| 11:19.14 | niemeyer | salgado: It is somewhat logical from an implementation perspective, but sucks a bit that it surfaces as this behavior |
| 11:24.17 | salgado | indeed, it's a bit confusing |
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